Submission #1553863

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Source Code Expand

#include<iostream>
#include<string>
using namespace std;
typedef long long ll;
int main()
{
	string s;
	cin>>s;
	ll sum=0,l=s.length();
	for(int i=0;i<l;i++)
	if(s[i]=='U') sum=sum+2*i+l-i-1;
	else sum=sum+i+2*(l-i-1);
	printf("%lld\n",sum);
	return 0;
}

Submission Info

Judge Result