Submission #1310279

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Source Code Expand

#include<bits/stdc++.h>

using namespace std;
typedef long long ll;
int main(){
  int n; cin >> n;
  ll a; cin >> a;
  ll b; cin >> b;
  if(a > b){
    cout << 0 << "\n";
    return 0;
  }
  if(n == 1){
    if(a == b) cout << 1 << "\n";
    else cout << 0 << "\n";
    return 0;
  }
  //so a <= b and n >= 2
  ll mn = b + (n-1) * a;
  ll mx = a + (n-1) * b;
  cout << mx - mn + 1 << "\n";
}

Submission Info

Judge Result