Submission #1777398

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Source Code Expand

#include<bits/stdc++.h>

using namespace std;
typedef long long ll;

int main(){
  string s;
  cin>>s;
  ll mx=-1,ans=0;
  for(ll i=0;i<s.size();i++){
    ll n=s.size()-i-1;
    if(s[i]=='U')ans+=2*i+n;
    else ans+=2*n+i;
  }
  
  cout<<ans<<endl;
  return 0;
}

Submission Info

Judge Result